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Perfect reply shambavi.
- 969 views
- 2 answers
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Hi Ria,
For word problems(age related), create a table with different time periods whichever mentioned in the question, so that it gives you a clarity in constructing an equation.
5 years ago
Now
2 years later
Jake
j
j+2
Mark
3(j+2)
3(j+2)+5
If jake is “j” years old now, then in 2 years, he will j+2.
Question says: Five years ago, Mark is 3 times older than Jack will be in 2 years.
So Mark five years ago,
3(j+2).
So now he will be,
3(j+2)+5
= 3j+11.
So the answer is D.
Hope that helps.
- 814 views
- 1 answers
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Hi Ria,
Whenever you find difficulty in constructing the equation. Always start plugging in.
If n = 2,
Total amount first stage is 1000.
And these 2 people persuade another 2 people each, so there are 4 people totally the persuaded. So total amount is 2000 in second stage.
So that’s all, you can understand that, if n people in first stage, then n^2 people in second stage.
The number of people donated at the first stage – n, So, total amount – 500n;
The number of people donated at the second – n^2, So, total amount – 500n^2;
Total amount donated – 500n+500n^2
(1) The first n people donated 1/16 of the total amount donated .
16(500n)=500n+500n^2 . “n” has to be positive.
n=15.
Sufficient.
(2) The total amount donated was $120,000. “n” has to be positive.
500n+500n^2=120,000
n=15. Again “n” is positive.
Sufficient.
So the answer is D.
- 679 views
- 2 answers
- 0 votes
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Hi Ria,
We have discussed the same question in detail in our OG videos.
Kindly refer to that.
You can write a mail to our prep/support team if you could not locate the same.
- 681 views
- 1 answers
- 0 votes
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Hi Ria,
We have discussed the same question in detail in our OG videos.
Kindly refer to that.
You can write a mail to our prep/support team if you could not locate the same.
- 647 views
- 1 answers
- 0 votes
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Hi Ria,
We have discussed the same question in detail in our OG videos.
Kindly refer to that.
You can write a mail to our prep/support team if you could not locate the same.
- 828 views
- 3 answers
- 0 votes
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Hi Ria,
We have discussed the same question in detail in our videos.
Kindly refer to that.
You can write a mail to our prep/support team if you could not locate the same.
- 694 views
- 1 answers
- 0 votes
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Hi Nirvan,
We are sorry to hear about your GMAT experience at Mysore better.
We can understand your pain because every second in exams like GMAT is very crucial.
We appreciate your effort for writing this post and this will definitely help students who is looking Mysore centre as an option.
May I suggest you report this issue in the GMAC official website. So that they fix this issue.
Thanks once again.
- 1486 views
- 1 answers
- 0 votes
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Hi Kukrejaria,
How you use alligation here ? Alligation method is helpful only when you have a resultant solution.
This is just a straight forward ratio question.
15 gram = 100 cubic centimetres
then 45 cubic centimetres = how many grams ?
So,
15/100 = ? / 45
So, ? = 6.75
So the answer is E.
Hope it is clear.
- 721 views
- 2 answers
- 0 votes
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Hi Kukrejaria,
Here given P is 30! (30 factorial).
Question is :
If 3^k is factor of 30!, then what is the maximum value of k ?
All we need to do is count the number of 3’s in the 30!.
So,
3 , 6, 9, 12, 15,18, 21, 24,27 and 30.
Above is the list, where we find the 3’s in the 30 factorial.
But in the above list,
9, 18 – counts for two three’s because you have 3^2 in it.
and 27 – counts for three 3’s in it, because 3^3 = 27.
So there are totally, 14 three’s in it.
So the answer is C.
Shortcut to find the same would be,
Find 3’s, 3^2’s and 3^3’s like I have done below,
(30/ 3) + (30/ 3^2) + (30 / 3^3)
= 10 + 3 + 1
= 14.
Hope this helps.
- 850 views
- 2 answers
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