DS …OA is A..
If list S contains nine distinct integers, at least one of which is negative, is the median of the integers in list S positive?
(1) The product of the nine integers in list S is equal to the median of list S.
(2) The sum of all nine integers in list S is equal to the median of list S.
I chose E since it is mentioned in question that atleast one is (-)ve
1st case: one member is negative, so multiplication of all 9 integer will be negative hence median will not be positive…
2nd case: all members are negative so multiplication of all 9 int will be negative and so median will not be positive.
3rd case: suppose even number of members are -ve ( for example 8 members are negative and one is positive) then multiplication of 9 integer will be +ve and so the median… will be positive
So not sufficient
But OA is A…. where i went wrong… !! Can someone please explain.
Hi Ankita,
Here first you need to understand is, statements are true information, so you have to pick values accordingly.
Given,
Set has 9 distinct integers, with alteast one member has to be negative.
Question is, Is median is positive ?
Median: Middle value in the List arranged from least to the greatest.
Statement I is sufficient:
Since they have told product of all the integers is equal to the median,
Only way you could achieve this is “0” being the median.
You can try any list of values , you cannot have median equal to the product of all the values in the list, unless the median is zero.
All the three cases, which you mentioned above is not right, because you cannot disprove the statement, you have to take the statement as a fact and solve the question.
Statement II is insufficient:
Because, if
list is -4,-3,-2,-1,0,1,2,3,4 then the answer to the question is NO. Here median is zero
But if,
List is -11,-2,-1,0,1,2,3,4,5 then the answer to the question is YES. here median is one.
So the answer is A.
Hope this helps
