Advanced Docs DS
25).Is mx + ky > kx + my?
I. m > k
II. x > y
According to me the answer should be C but the answer in the explanation says that it is A.
The relevant extracts from the explanation are reproduced below:
mx -my > kx-ky
m(x-y) > k (x-y)
Is m >k
Statement I is sufficient: m>k, sufficient Statement II is insufficient: Nothing about m and k. Insufficient. So the answer is A.
What I do not understand is how can we cancel out (x-y) from both sides since- (a) we do not know the sign so the inequlaity sign might get reversed; and (b) what if x-y=0.
PLease let me know if my though process is correct or if I am missing something here.
Hi User,
You are absolutely right. Both you are reasoning are right.
thanks for letting us know. The changes has been made.
We cant cancel out here (x-y) because we have inequalities both sides.
While writing the explanation, author was in the assumption that x-y is positive, which is not the case here.
We get that information only if we consider the statement II,
So the answer is C.
