How to go about this question?
From the consecutive integers -10 to 10 inclusive, 20 integers are randomly chosen with repetitions allowed. What is the least possible value of the product of the 20 integers?
A. (-10)^20
B. (-10)^10
C. 0
D. –(10)^19
E. –(10)^20
Hi Kukrejaria,
It is a pretty straight forward question.
There are totally 21 integers between -10 to 10 inclusive(Remember we also have zero in this range).
We have to chose integers from the above list, such that the product of all the 20 integers should be the least.
Product of 19 Positive integers * one negative integer will be negative. Remember we can pick the same integer any number of times. Repetition is allowed.
10 is the greatest number and -10 is the least number in the given list.
So, that should be the idea here, 19 positive ten multiplied with one negative ten.
So answer is -(10)^ 20.
So the answer is E here.
