PS OG Q218

Default Asked on March 29, 2015 in Problem Solving.
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6 Answer(s)

Hi Arnab, I hope this
helps.

 

Let us Assume T = (1.a,
1.b, etc). This consists of 3o decimals.

 Now let’s find out E. In E Tenths digit even
rounded up and tenths digit odd rounded down. 1/3 of the decimals of the
decimals in T whose tenths digit is even. So there are 10 decimals like that.

So say for an example say if
decimal value is 1.2 is rounded to 2. If it is 1.1 it is rounded to 1.


So therefore E = 40 (due to rounding of ten even and 20 odd) .

Since the question is
asking for possible value. Let find out minimum and maximum values.

S max = 30 + 10(.8) +
20(.9) = 56( maximum value for an even and odd in tenths place ) 
S min = 30 + 10(.2) + 20(.1) = 34 ( minimum value for an even and odd in
tenths place ) 

E-S min = 40 – 56 = -16 
E-S max = 40 – 34 = 6 
Thus, the min/max of E is -16 and 6, so I , II apply. 

 

III statement is beyond
the range.

So answer is C. I and II
only.

Expert Answered on March 31, 2015.
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Can any one please show me a easy way of solving this question as the solution given in the OG has confused me

List T consists of 30 positive decimals, none of which is an integer, and the sum of the 30 decimals is S. The estimated sum of the 30 decimals, E, is defined as follows. Each decimal in T whose tenths digit is even is rounded up to the nearest integer, and each decimal in T whose tenths digit is odd is rounded down to the nearest integer; E is the sum of the resulting integers. If 1/3 of the decimals in T have a tenths digit that is even , which of the following is a possible value of E-S?
I. -16
II. 16
III. 10
(A) I only
(B) I and II only
(C) I and III only
(D) II and III only
(E) I,II and III
Default Answered on March 29, 2015.
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Thank you for the explanation. 

Default Answered on March 31, 2015.
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Glad it helped.

Expert Answered on April 17, 2015.
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@arnab  I suppose II option is 6 ????

Default Answered on June 8, 2015.
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yes answer option II  is 6 only. Typo error.

Expert Answered on June 9, 2015.
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